Matematika Materi : Persamaan pangkat [tex] \sqrt{3} {}^{x + 3} = ( \frac{1}{81} ) {}^{6 - x} [/tex]​

fabianhauckulv – April 07, 2023

Materi : Persamaan pangkat
[tex] \sqrt{3} {}^{x + 3} = ( \frac{1}{81} ) {}^{6 - x} [/tex]
​

Materi : Bentuk Akar dan Pangkat

(√3)×+³ = (1/81)⁶-×

3¹/²(×+³) = 3⁴(⁶-×)

½( x + 3 ) = 4( 6 - x )

x + 3 = 8( 6 - x )

x + 3 = 48 - 8x

x + 8x = 48 - 3

9x = 45

x = 45/9

x = 5

Semoga bisa membantu

[tex] \boxed{ \colorbox{navy}{ \sf{ \color{lightblue}{ Answer\:by\: BLUEBRAXGEOMETRY}}}} [/tex]

[answer.2.content]